2y=(1/2)y^2

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Solution for 2y=(1/2)y^2 equation: 



2y=(1/2)y^2

We move all terms to the left:

2y-((1/2)y^2)=0



Domain of the equation: 2)y^2)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

2y-((+1/2)y^2)=0

We multiply all the terms by the denominator


2y*2)y^2)-((+1=0

Wy multiply elements

4y^2+1=0

a = 4; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·4·1
Δ = -16
Delta is less than zero, so there is no solution for the equation

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